4/(x+2)^4-5/(x+2)^2=0

Solution for 4/(x+2)^4-5/(x+2)^2=0 equation:

4/(x+2)^4-5/(x+2)^2=0


Domain of the equation: (x+2)^4!=0

x∈R



Domain of the equation: (x+2)^2!=0

x∈R


We calculate fractions


(4*(x+2)^2)/((x+2)^4*(x+2)^2)+(-5*(x+2)^4)/((x+2)^4*(x+2)^2)=0


We calculate terms in parentheses: +(4*(x+2)^2)/((x+2)^4*(x+2)^2), so:

4*(x+2)^2)/((x+2)^4*(x+2)^2

We multiply all the terms by the denominator


4*(x+2)^2)

We multiply parentheses

4x+

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)



We calculate terms in parentheses: +(-5*(x+2)^4)/((x+2)^4*(x+2)^2), so:

-5*(x+2)^4)/((x+2)^4*(x+2)^2

We multiply all the terms by the denominator


-5*(x+2)^4)

We multiply parentheses

-5x-

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)


We get rid of parentheses

4x-5x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0